There are 2 trains P and Q moving in same direction. They are of equal length and cross a stationary pole in 5 seconds and 6 seconds respectively. In how much time would they cross each other?30 seconds11 seconds60 seconds1 seconds
Question
There are 2 trains P and Q moving in same direction. They are of equal length and cross a stationary pole in 5 seconds and 6 seconds respectively. In how much time would they cross each other?30 seconds11 seconds60 seconds1 seconds
Solution
To solve this problem, we first need to understand that the speed of a train is given by the distance it covers divided by the time it takes. In this case, the distance is the length of the train and the time is the time it takes to cross the pole.
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Calculate the speed of train P: Since train P crosses a pole (which is essentially its own length) in 5 seconds, its speed is 1 length per 5 seconds or 1/5 length/second.
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Calculate the speed of train Q: Similarly, train Q's speed is 1 length per 6 seconds or 1/6 length/second.
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Calculate the relative speed of the two trains: Since they are moving in the same direction, we subtract the speed of train Q from that of train P. So, the relative speed is 1/5 - 1/6 = 1/30 length/second.
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Calculate the time they take to cross each other: When two trains cross each other, they cover a distance of the sum of their lengths. Since the two trains are of equal length, the total distance is 2 lengths. So, the time taken to cross each other is the total distance divided by their relative speed, which is 2 lengths / (1/30 length/second) = 60 seconds.
So, the two trains would cross each other in 60 seconds.
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