Here is a Python program that can help Bethany determine if a number is a strong number or not:

```python
def factorial(n):
if n == 0:
return 1
else:
return n * factorial(n-1)

def is_strong_number(number):
temp = number
sum = 0
while temp 0:
digit = temp % 10
sum += factorial(digit)
temp //= 10
if sum == number:
return "Strong number"
else:
return "Not a strong number"

# Test the function
number = int(input("Enter a number: "))
print(is_strong_number(number))
```

This program works by first defining a helper function `factorial()` to calculate the factorial of a number. Then it defines the main function `is_strong_number()`. This function takes a number as input, calculates the sum of the factorials of its digits, and checks if this sum is equal to the original number. If it is, the function returns "Strong number", otherwise it returns "Not a strong number". Finally, the program prompts the user to enter a number and prints whether this number is a strong number or not.

Question

Here is a Python program that can help Bethany determine if a number is a strong number or not:

```python
def factorial(n):
    if n == 0:
        return 1
    else:
        return n * factorial(n-1)

def is_strong_number(number):
    temp = number
    sum = 0
    while temp > 0:
        digit = temp % 10
        sum += factorial(digit)
        temp //= 10
    if sum == number:
        return "Strong number"
    else:
        return "Not a strong number"

# Test the function
number = int(input("Enter a number: "))
print(is_strong_number(number))
```

This program works by first defining a helper function `factorial()` to calculate the factorial of a number. Then it defines the main function `is_strong_number()`. This function takes a number as input, calculates the sum of the factorials of its digits, and checks if this sum is equal to the original number. If it is, the function returns "Strong number", otherwise it returns "Not a strong number". Finally, the program prompts the user to enter a number and prints whether this number is a strong number or not.

Knowee AI · Accepted Answer

Here is a Python program that can help Bethany determine if a number is a strong number or not:

```python
def factorial(n):
    if n == 0:
        return 1
    else:
        return n * factorial(n-1)

def is_strong_number(number):
    temp = number
    sum = 0
    while temp > 0:
        digit = temp % 10
        sum += factorial(digit)
        temp //= 10
    if sum == number:
        return "Strong number"
    else:
        return "Not a strong number"

# Test the function
number = int(input("Enter a number: "))
print(is_strong_number(number))
```

This program works by first defining a helper function `factorial()` to calculate the factorial of a number. Then it defines the main function `is_strong_number()`. This function takes a number as input, calculates the sum of the factorials of its digits, and checks if this sum is equal to the original number. If it is, the function returns "Strong number", otherwise it returns "Not a strong number". Finally, the program prompts the user to enter a number and prints whether this number is a strong number or not.

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