The cost of 3 apples, 2 mangos and 4 oranges is Rs.43. The cost of 5 apples, 3 mangos and 6 oranges is Rs.66. Find the cost of one apple?a.Rs.4b.Rs.6c.Rs.5d.Rs.3
Question
The cost of 3 apples, 2 mangos and 4 oranges is Rs.43. The cost of 5 apples, 3 mangos and 6 oranges is Rs.66. Find the cost of one apple?a.Rs.4b.Rs.6c.Rs.5d.Rs.3
Solution
This problem can be solved using the method of simultaneous equations.
Let's denote: A = cost of one apple M = cost of one mango O = cost of one orange
From the problem, we have the following two equations:
3A + 2M + 4O = 43 (equation 1) 5A + 3M + 6O = 66 (equation 2)
We can multiply equation 1 by 5 and equation 2 by 3 to make the coefficients of A the same in both equations:
15A + 10M + 20O = 215 (equation 3) 15A + 9M + 18O = 198 (equation 4)
Now, we can subtract equation 4 from equation 3 to find the cost of one mango and two oranges:
M + 2O = 17 (equation 5)
We don't have enough information to find the cost of one apple directly, so the problem as stated doesn't have a unique solution. We would need another equation that relates the cost of apples, mangos, and oranges to solve for A.
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