The molar conductivity (Λ) is given by the equation Λ = K/R, where K is the cell constant and R is the resistance.

For solution 1, we have:
Λ1 = K/R1 = 129 m^-1 / 100 Ω = 1.29 m^-1 Ω^-1

For solution 2, we have:
Λ2 = K/R2 = 129 m^-1 / 50 Ω = 2.58 m^-1 Ω^-1

The ratio of molar conductivity of solution 1 to solution 2 is therefore:
Λ1/Λ2 = 1.29 m^-1 Ω^-1 / 2.58 m^-1 Ω^-1 = 0.5

So, the value of x is 0.5 × 10^3 = 500.

Therefore, the nearest integer value of x is 500.

Question

The molar conductivity (Λ) is given by the equation Λ = K/R, where K is the cell constant and R is the resistance.

For solution 1, we have:
Λ1 = K/R1 = 129 m^-1 / 100 Ω = 1.29 m^-1 Ω^-1

For solution 2, we have:
Λ2 = K/R2 = 129 m^-1 / 50 Ω = 2.58 m^-1 Ω^-1

The ratio of molar conductivity of solution 1 to solution 2 is therefore:
Λ1/Λ2 = 1.29 m^-1 Ω^-1 / 2.58 m^-1 Ω^-1 = 0.5

So, the value of x is 0.5 × 10^3 = 500.

Therefore, the nearest integer value of x is 500.

Knowee AI · Accepted Answer

The molar conductivity (Λ) is given by the equation Λ = K/R, where K is the cell constant and R is the resistance.

For solution 1, we have:
Λ1 = K/R1 = 129 m^-1 / 100 Ω = 1.29 m^-1 Ω^-1

For solution 2, we have:
Λ2 = K/R2 = 129 m^-1 / 50 Ω = 2.58 m^-1 Ω^-1

The ratio of molar conductivity of solution 1 to solution 2 is therefore:
Λ1/Λ2 = 1.29 m^-1 Ω^-1 / 2.58 m^-1 Ω^-1 = 0.5

So, the value of x is 0.5 × 10^3 = 500.

Therefore, the nearest integer value of x is 500.

Question