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Given that lim x→1 f(x) = 4    lim x→1 g(x) = −5    lim x→1 h(x) = 0,find the limits, if they exist. (If an answer does not exist, enter DNE.)(a)    lim x→1 [f(x) + 5g(x)](b)    lim x→1 [g(x)]3(c)    lim x→1 f(x)(d)    lim x→1 5f(x)g(x)(e)    lim x→1 g(x)h(x)(f)    lim x→1 g(x)h(x)f(x)

Question

Given that lim x→1 f(x) = 4    lim x→1 g(x) = −5    lim x→1 h(x) = 0,find the limits, if they exist. (If an answer does not exist, enter DNE.)(a)    lim x→1 f(x) + 5g(x)    lim x→1 [g(x)]3(c)    lim x→1 f(x)(d)    lim x→1 5f(x)g(x)(e)    lim x→1 g(x)h(x)(f)    lim x→1 g(x)h(x)f(x)

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Solution

(a) The limit of the sum of two functions is the sum of their limits. So, lim x→1 [f(x) + 5g(x)] = lim x→1 f(x) + 5lim x→1 g(x) = 4 + 5(-5) = 4 - 25 = -21.

(b) The limit of a function raised to a power is the limit of the function raised to that power. So, lim x→1 [g(x)]^3 = (lim x→1 g(x))^3 = (-5)^3 = -125.

(c) The limit of f(x) as x approaches 1 is given as 4. So, lim x→1 f(x) = 4.

(d) The limit of the product of two functions is the product of their limits. So, lim x→1 5f(x)g(x) = 5lim x→1 f(x) * lim x→1 g(x) = 54*(-5) = -100.

(e) The limit of the product of two functions is the product of their limits. So, lim x→1 g(x)h(x) = lim x→1 g(x) * lim x→1 h(x) = -5*0 = 0.

(f) The limit of the product of three functions is the product of their limits. So, lim x→1 g(x)h(x)f(x) = lim x→1 g(x) * lim x→1 h(x) * lim x→1 f(x) = -504 = 0.

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