To solve this problem, we can use the gas law formula which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume (P1V1 = P2V2), assuming that temperature and the amount of gas are constant.

Here are the steps:

1. Identify the initial pressure (P1), initial volume (V1), and final pressure (P2). In this case, P1 is 830 mmHg, V1 is 2,785 L, and P2 is 760 mmHg (standard pressure).

2. Plug these values into the formula: (830 mmHg * 2,785 L) = (760 mmHg * V2)

3. Solve for V2 (the final volume). Divide both sides of the equation by 760 mmHg to isolate V2: V2 = (830 mmHg * 2,785 L) / 760 mmHg

4. Calculate the value to find the volume of the propane at standard pressure.

Remember to keep the units consistent throughout the calculation.

Question

To solve this problem, we can use the gas law formula which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume (P1V1 = P2V2), assuming that temperature and the amount of gas are constant.

Here are the steps:

1. Identify the initial pressure (P1), initial volume (V1), and final pressure (P2). In this case, P1 is 830 mmHg, V1 is 2,785 L, and P2 is 760 mmHg (standard pressure).

2. Plug these values into the formula: (830 mmHg * 2,785 L) = (760 mmHg * V2)

3. Solve for V2 (the final volume). Divide both sides of the equation by 760 mmHg to isolate V2: V2 = (830 mmHg * 2,785 L) / 760 mmHg

4. Calculate the value to find the volume of the propane at standard pressure.

Remember to keep the units consistent throughout the calculation.

Knowee AI · Accepted Answer

To solve this problem, we can use the gas law formula which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume (P1V1 = P2V2), assuming that temperature and the amount of gas are constant.

Here are the steps:

1. Identify the initial pressure (P1), initial volume (V1), and final pressure (P2). In this case, P1 is 830 mmHg, V1 is 2,785 L, and P2 is 760 mmHg (standard pressure).

2. Plug these values into the formula: (830 mmHg * 2,785 L) = (760 mmHg * V2)

3. Solve for V2 (the final volume). Divide both sides of the equation by 760 mmHg to isolate V2: V2 = (830 mmHg * 2,785 L) / 760 mmHg

4. Calculate the value to find the volume of the propane at standard pressure.

Remember to keep the units consistent throughout the calculation.

29. A gas tank holds 2,785 L of propane at 830 mmHg. What is the volume of the propane at standard pressure (760 mmHg)?

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