This tree diagram shows the tossing of an unfair coin followed by drawing one bead from a cup containing 7 red (R), 4 yellow (Y) and 5 blue (B) beads. For the coin, P(H) = 13 and P(T) = 23 where H is heads and T is tails.Find P(tossing a Head on the coin AND a Red bead). (Enter your answer as a fraction.)

Complete the following statements based on the pattern you have observed, without a tree diagram. a) If a coin was tossed 5 times, the probability of getting 5 heads would be: ______________ b) If a coin was tossed 6 times, the probability of getting 6 heads would be: ______________c) If a coin was tossed 7 times, the probability of getting 7 heads would be: ______________ d)   If a coin was tossed 10 times, the probability of getting 10 heads would be: ______________         16.  Explain how you used the pattern to answer question 15 a,b,c,d 17.  Justify (explain) why your rule works for any number of times a coin is tossed

Two unfair coins are tossed with the probability of a tail equal to 0.25. Calculate the probability ofgetting:(a) No heads.(b) Exactly one head.(c) At least one head.

ProbabilityTwo coins are tossed, find the probability that one head only is obtained.Options1/41/61/21/3

A jar of 150 jelly beans contains 20 red jelly beans, 38 yellow, 26 green, 22 purple, 28 blue, and the rest are orange.Let B = the event of getting a blue jelly bean.Let G = the event of getting a green jelly bean.Let O = the event of getting an orange jelly bean.Let P = the event of getting a purple jelly bean.Let R = the event of getting a red jelly bean.Let Y = the event of getting a yellow jelly bean.Find P(P). (Enter your probability as a fraction.)

A coin is tossed three times. An outcome is represented by a string of the sort HTT (meaning heads on the first toss, followed by two tails).The 8 outcomes are listed below. Assume that each outcome has the same probability.Complete the following. Write your answers as fractions.