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A rectangular piece of paper with length 39cm and width 20cm has two semicircles cut out of it, as shown below.Find the area of the paper that remains. Use the value 3.14 for π, and do not round your answer. Be sure to include the correct unit in your answer.20cm39cm

Question

A rectangular piece of paper with length 39cm and width 20cm has two semicircles cut out of it, as shown below.Find the area of the paper that remains. Use the value 3.14 for π, and do not round your answer. Be sure to include the correct unit in your answer.20cm39cm

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Solution

The problem seems to be missing a diagram, but based on the description, it sounds like the two semicircles are cut out from the shorter ends of the rectangle.

Here's how you can solve this:

Step 1: Calculate the area of the rectangle. The area of a rectangle is given by the formula length × width. So, the area of the rectangle is 39cm × 20cm = 780 square cm.

Step 2: Calculate the area of the two semicircles. The diameter of each semicircle is the width of the rectangle, which is 20cm. Therefore, the radius of each semicircle is 20cm ÷ 2 = 10cm. The area of a circle is given by the formula πr². So, the area of each semicircle is 1/2 × π × (10cm)² = 1/2 × 3.14 × 100cm² = 157 square cm. Since there are two semicircles, their total area is 2 × 157 square cm = 314 square cm.

Step 3: Subtract the area of the semicircles from the area of the rectangle. The area of the paper that remains after the semicircles are cut out is 780 square cm - 314 square cm = 466 square cm.

So, the area of the paper that remains is 466 square cm.

This problem has been solved

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