The difference of squares is a term used in algebra to describe the difference between two square numbers. It is represented by the formula a² - b² = (a+b)(a-b).

In the given polynomial x² + ?x - 36, we want to find the value of ? that will make the polynomial a difference of squares.

A difference of squares can be factored into (a+b)(a-b). So, we want to rewrite x² + ?x - 36 in this form.

If we look at the -36 at the end of the polynomial, we can see that it is a square number (since 6² = 36). This suggests that we might be able to rewrite the polynomial as (x+6)(x-6).

However, if we try to expand (x+6)(x-6), we get x² - 36, not x² + ?x - 36. This means that the ? must be 0, because there is no x term in x² - 36.

So, the answer is B. 0.

Question

The difference of squares is a term used in algebra to describe the difference between two square numbers. It is represented by the formula a² - b² = (a+b)(a-b).

In the given polynomial x² + ?x - 36, we want to find the value of ? that will make the polynomial a difference of squares.

A difference of squares can be factored into (a+b)(a-b). So, we want to rewrite x² + ?x - 36 in this form.

If we look at the -36 at the end of the polynomial, we can see that it is a square number (since 6² = 36). This suggests that we might be able to rewrite the polynomial as (x+6)(x-6).

However, if we try to expand (x+6)(x-6), we get x² - 36, not x² + ?x - 36. This means that the ? must be 0, because there is no x term in x² - 36.

So, the answer is B. 0.

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The difference of squares is a term used in algebra to describe the difference between two square numbers. It is represented by the formula a² - b² = (a+b)(a-b).

In the given polynomial x² + ?x - 36, we want to find the value of ? that will make the polynomial a difference of squares.

A difference of squares can be factored into (a+b)(a-b). So, we want to rewrite x² + ?x - 36 in this form.

If we look at the -36 at the end of the polynomial, we can see that it is a square number (since 6² = 36). This suggests that we might be able to rewrite the polynomial as (x+6)(x-6).

However, if we try to expand (x+6)(x-6), we get x² - 36, not x² + ?x - 36. This means that the ? must be 0, because there is no x term in x² - 36.

So, the answer is B. 0.

In the polynomial below, what number should replace the question mark to produce a difference of squares?x2 + ?x - 36A.36B.0C.6D.12SUBMITarrow_backPREVIOUS

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