The alkyl bromide that will give only one alkene upon treatment with a strong base is 1-bromohexane.

Here's why:

1. (S)-2-bromohexane and (R)-2-bromohexane: These are chiral molecules and will produce two different alkenes due to the formation of a more substituted alkene (major product) and a less substituted alkene (minor product) during the elimination reaction.

2. 2-bromo-2-methylpentane: This will also produce two different alkenes due to the formation of a more substituted alkene (major product) and a less substituted alkene (minor product) during the elimination reaction.

3. 1-bromohexane: This will only produce one alkene, hexene, upon treatment with a strong base. This is because the bromine atom is located at the end of the chain, so there's only one β-carbon available for the elimination reaction. Therefore, only one alkene can be formed.

Question

The alkyl bromide that will give only one alkene upon treatment with a strong base is 1-bromohexane.

Here's why:

1. (S)-2-bromohexane and (R)-2-bromohexane: These are chiral molecules and will produce two different alkenes due to the formation of a more substituted alkene (major product) and a less substituted alkene (minor product) during the elimination reaction.

2. 2-bromo-2-methylpentane: This will also produce two different alkenes due to the formation of a more substituted alkene (major product) and a less substituted alkene (minor product) during the elimination reaction.

3. 1-bromohexane: This will only produce one alkene, hexene, upon treatment with a strong base. This is because the bromine atom is located at the end of the chain, so there's only one β-carbon available for the elimination reaction. Therefore, only one alkene can be formed.

Knowee AI · Accepted Answer

The alkyl bromide that will give only one alkene upon treatment with a strong base is 1-bromohexane.

Here's why:

1. (S)-2-bromohexane and (R)-2-bromohexane: These are chiral molecules and will produce two different alkenes due to the formation of a more substituted alkene (major product) and a less substituted alkene (minor product) during the elimination reaction.

2. 2-bromo-2-methylpentane: This will also produce two different alkenes due to the formation of a more substituted alkene (major product) and a less substituted alkene (minor product) during the elimination reaction.

3. 1-bromohexane: This will only produce one alkene, hexene, upon treatment with a strong base. This is because the bromine atom is located at the end of the chain, so there's only one β-carbon available for the elimination reaction. Therefore, only one alkene can be formed.

Which of the following alkyl bromides will give only one alkene upon treatment with a strong base?Select answer from the options below(S)-2-bromohexane1-bromohexane 2-bromo-2-methylpentane (R)-2-bromohexane

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