Define a function front_times(str1, n) that returns n copies of the front. n is a non-negative int. The front of the string is the first 3 chars, or whatever is there if the string is less than length 3.Examplestr1 = 'Chocolate'front_times(str1, 2) → 'ChoCho'Expected output:'ChoCho'str2 = 'ab'front_times(str2, 2) → 'abab'Expected output:'abab'Hint:use string slicing to get substringuse str * num, you will get repeat copy of str.for example, 'hello' * 3 => 'hellohellohello'

To define the function front_times(str1, n), follow these steps:

1. Start by writing the function definition: def front_times(str1, n):
2. Check if the length of str1 is less than 3 using an if statement: if len(str1) < 3:
3. Inside the if statement, assign the value of str1 to a variable called front: front = str1
4. If the length of str1 is greater than or equal to 3, use string slicing to assign the first 3 characters of str1 to the variable front: front = str1[:3]
5. Outside the if statement, return the concatenation of front repeated n times using the * operator: return front * n

Here's the complete code:

def front_times(str1, n):
    if len(str1) < 3:
        front = str1
    else:
        front = str1[:3]
    return front * n

Now, you can call the function with different inputs to test it:

str1 = 'Chocolate'
print(front_times(str1, 2))  # Output: 'ChoCho'

str2 = 'ab'
print(front_times(str2, 2))  # Output: 'abab'

I hope this helps!