Given a positive integer n, find the smallest integer which has exactly the same

Given a positive integer n, return the smallest positive integer that is a multiple of both 2 and n. Example 1:Input: n = 5Output: 10Explanation: The smallest multiple of both 5 and 2 is 10.Example 2:Input: n = 6Output: 6Explanation: The smallest multiple of both 6 and 2 is 6. Note that a number is a multiple of itself.

Compute An, where n ≥ 1 is an integer

Problem StatementNaveen is tasked with a mathematical challenge that requires finding the smallest positive number that is evenly divisible by all integers from 1 to a given positive number, 'n' received as input from the user. In simpler terms, find the smallest number that can be divided by all whole numbers from 1 up to 'n' without any remainder. Make sure to employ the break statement to ensure efficiency in the program.ExampleInput: 10Output: 2520Explanation: Start with the prime factorization of each number from 1 to 10:1 = 12 = 23 = 34 = 2 * 25 = 56 = 2 * 37 = 78 = 2 * 2 * 29 = 3 * 310 = 2 * 5Identify the maximum power of each prime factor:23 (from 8)32 (from 9)5 (from 5)7 (from 7)Multiply these together:23 * 32 * 5 * 7 = 2520.So, 2520 is the smallest number that can be evenly divided by all the whole numbers from 1 to 10.Note: This question helps in clearing the AMCAT exam.Input format :The input consists of a single integer n.Output format :The output displays the smallest positive number that is divisible by all integers from 1 to n without leaving any remainder.Refer to the sample output for the formatting specifications.Code constraints :In the given scenario, the test cases fall under the following constraints:2 ≤ n ≤ 20Sample test cases :Input 1 :10Output 1 :2520Input 2 :2Output 2 :2Input 3 :20Output 3 :232792560

Find the smallest natural number 'n' which becomes a perfect square when divided by 3 and a perfect cube when divided by 5.

Find the least number which when divided by 10, 11, 15 and 22 leaves 3, 4, 8 and 15 as remainders, respectively333323423433