A customer is buying two bags of potatoes, bag A and bag B. The mass of bag B is 3 kg more than twice the mass of bag A. The total mass of both bags of potatoes is 27 kg. Determine the mass of each bag of potatoes. *1 pointMass of A=8kg, Mass of B=16kgMass of A= 10kg, Mass of B= 19kgMass of A= 8kg, Mass of B= 19kg
Question
A customer is buying two bags of potatoes, bag A and bag B. The mass of bag B is 3 kg more than twice the mass of bag A. The total mass of both bags of potatoes is 27 kg. Determine the mass of each bag of potatoes. *1 pointMass of A=8kg, Mass of B=16kgMass of A= 10kg, Mass of B= 19kgMass of A= 8kg, Mass of B= 19kg
Solution
Let's denote the mass of bag A as "a" and the mass of bag B as "b".
From the problem, we know two things:
-
The mass of bag B is 3 kg more than twice the mass of bag A. This can be written as: b = 2a + 3
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The total mass of both bags of potatoes is 27 kg. This can be written as: a + b = 27
Now we can solve these equations step by step:
First, substitute the first equation (b = 2a + 3) into the second equation (a + b = 27). This gives us: a + 2a + 3 = 27
Combine like terms: 3a + 3 = 27
Subtract 3 from both sides: 3a = 24
Divide both sides by 3: a = 8
Now that we know a = 8, we can substitute this into the first equation to find b: b = 2*8 + 3 = 19
So, the mass of bag A is 8 kg and the mass of bag B is 19 kg.
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