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A customer is buying two bags of potatoes, bag A and bag B. The mass of bag B is 3 kg more than twice the mass of bag A. The total mass of both bags of potatoes is 27 kg. Determine the mass of each bag of potatoes.  *1 pointMass of A=8kg, Mass of B=16kgMass of A= 10kg, Mass of B= 19kgMass of A= 8kg, Mass of B= 19kg

Question

A customer is buying two bags of potatoes, bag A and bag B. The mass of bag B is 3 kg more than twice the mass of bag A. The total mass of both bags of potatoes is 27 kg. Determine the mass of each bag of potatoes.  *1 pointMass of A=8kg, Mass of B=16kgMass of A= 10kg, Mass of B= 19kgMass of A= 8kg, Mass of B= 19kg

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Solution

Let's denote the mass of bag A as "a" and the mass of bag B as "b".

From the problem, we know two things:

  1. The mass of bag B is 3 kg more than twice the mass of bag A. This can be written as: b = 2a + 3

  2. The total mass of both bags of potatoes is 27 kg. This can be written as: a + b = 27

Now we can solve these equations step by step:

First, substitute the first equation (b = 2a + 3) into the second equation (a + b = 27). This gives us: a + 2a + 3 = 27

Combine like terms: 3a + 3 = 27

Subtract 3 from both sides: 3a = 24

Divide both sides by 3: a = 8

Now that we know a = 8, we can substitute this into the first equation to find b: b = 2*8 + 3 = 19

So, the mass of bag A is 8 kg and the mass of bag B is 19 kg.

This problem has been solved

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