A sample of water was heated and allowed to cool down. The energy transferred to the surroundings was 132 300 J and the temperature changed from 70 °C to 25 °C.The specific heat capacity of water is 4200 J/kg°C.What was the mass of the sample of water?You must include units with your answer.
Question
A sample of water was heated and allowed to cool down. The energy transferred to the surroundings was 132 300 J and the temperature changed from 70 °C to 25 °C.The specific heat capacity of water is 4200 J/kg°C.What was the mass of the sample of water?You must include units with your answer.
Solution
To find the mass of the water sample, we can use the formula for heat transfer:
Q = mcΔT
where: Q = heat energy transferred (in joules) m = mass (in kg) c = specific heat capacity (in J/kg°C) ΔT = change in temperature (in °C)
We can rearrange the formula to solve for mass:
m = Q / (cΔT)
Substituting the given values:
m = 132,300 J / (4200 J/kg°C * (70°C - 25°C))
m = 132,300 J / (4200 J/kg°C * 45°C)
m = 132,300 J / 189,000 J/kg
m = 0.7 kg
So, the mass of the water sample was 0.7 kilograms.
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