The expression tansin−1u6 can be rewritten using the Pythagorean identity for sine and cosine.

Step 1: Recognize that sin−1u6 represents an angle whose sine is u/6. Let's call this angle θ. So, sinθ = u/6.

Step 2: Use the Pythagorean identity sin^2θ + cos^2θ = 1. This can be rearranged to find cosθ = sqrt(1 - sin^2θ) = sqrt(1 - (u/6)^2).

Step 3: The original expression is tanθ, which is sinθ/cosθ. Substituting the expressions we found for sinθ and cosθ, we get (u/6) / sqrt(1 - (u/6)^2).

So, tansin−1u6 = (u/6) / sqrt(1 - (u/6)^2).

Question

The expression tansin−1u6 can be rewritten using the Pythagorean identity for sine and cosine.

Step 1: Recognize that sin−1u6 represents an angle whose sine is u/6. Let's call this angle θ. So, sinθ = u/6.

Step 2: Use the Pythagorean identity sin^2θ + cos^2θ = 1. This can be rearranged to find cosθ = sqrt(1 - sin^2θ) = sqrt(1 - (u/6)^2).

Step 3: The original expression is tanθ, which is sinθ/cosθ. Substituting the expressions we found for sinθ and cosθ, we get (u/6) / sqrt(1 - (u/6)^2).

So, tansin−1u6 = (u/6) / sqrt(1 - (u/6)^2).

Knowee AI · Accepted Answer

The expression tansin−1u6 can be rewritten using the Pythagorean identity for sine and cosine.

Step 1: Recognize that sin−1u6 represents an angle whose sine is u/6. Let's call this angle θ. So, sinθ = u/6.

Step 2: Use the Pythagorean identity sin^2θ + cos^2θ = 1. This can be rearranged to find cosθ = sqrt(1 - sin^2θ) = sqrt(1 - (u/6)^2).

Step 3: The original expression is tanθ, which is sinθ/cosθ. Substituting the expressions we found for sinθ and cosθ, we get (u/6) / sqrt(1 - (u/6)^2).

So, tansin−1u6 = (u/6) / sqrt(1 - (u/6)^2).

Rewrite tansin−1u6 as an algebraic expression in u.=tansin−1u6

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