The area of circle A is equal to the sum of the area of two small circles with diameters of 6cm and 8cm. Then the diameter of circle A will be? 5 10 15 20
Question
The area of circle A is equal to the sum of the area of two small circles with diameters of 6cm and 8cm. Then the diameter of circle A will be? 5 10 15 20
Solution
To solve this problem, we first need to understand the formula for the area of a circle, which is πr², where r is the radius of the circle.
Step 1: Calculate the area of the two smaller circles.
The radius of the first small circle is 6cm/2 = 3cm. So, its area is π(3cm)² = 9π cm².
The radius of the second small circle is 8cm/2 = 4cm. So, its area is π(4cm)² = 16π cm².
Step 2: Add the areas of the two smaller circles together.
9π cm² + 16π cm² = 25π cm².
This is the area of circle A.
Step 3: Use the area of circle A to find its radius.
We know that the area of a circle is πr². So, we can set up the equation 25π cm² = πr² and solve for r.
Dividing both sides by π gives us r² = 25 cm², and taking the square root of both sides gives us r = 5 cm.
Step 4: Double the radius to find the diameter of circle A.
The diameter of a circle is twice its radius, so the diameter of circle A is 2 * 5 cm = 10 cm.
So, the diameter of circle A is 10 cm.
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