lim θ→0 8θ+tanθsinθ
Solution
The limit of the function as θ approaches 0 can be found by using L'Hopital's Rule, which states that the limit of a quotient of two functions as x approaches a certain value is equal to the limit of the quotients of their derivatives.
The function is given as (8θ + tanθ) / sinθ.
First, we need to find the derivatives of the numerator and the denominator.
The derivative of 8θ is 8, the derivative of tanθ is sec²θ, and the derivative of sinθ is cosθ.
So, the derivative of the numerator is 8 + sec²θ and the derivative of the denominator is cosθ.
Now, we substitute these into the function and take the limit as θ approaches 0.
lim θ→0 (8 + sec²θ) / cosθ
As θ approaches 0, sec²θ approaches 1 (since sec 0 = 1) and cosθ also approaches 1 (since cos 0 = 1).
So, the limit of the function as θ approaches 0 is (8 + 1) / 1 = 9.
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