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Some lipids contains carbon to carbon double bonds.Given the bond dissociation energies in the table, calculate the enthalpy change when one mole of hydrogen is added across one double bond. A.+1520 kJ/molB.-1520 kJ/molC.+120 kJ/molD.-120 kJ/mol

Question

Some lipids contains carbon to carbon double bonds.Given the bond dissociation energies in the table, calculate the enthalpy change when one mole of hydrogen is added across one double bond. A.+1520 kJ/molB.-1520 kJ/molC.+120 kJ/molD.-120 kJ/mol

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Solution

To answer this question, we need more information. Specifically, we need the bond dissociation energies for the relevant bonds. The question mentions a table, but the table is not provided.

In general, the enthalpy change (ΔH) for a reaction can be calculated using the formula:

ΔH = Σ(Bond energies of bonds broken) - Σ(Bond energies of bonds formed)

In this case, we are breaking a carbon-carbon double bond and forming two carbon-hydrogen bonds. So, we would need the bond dissociation energies for these bonds to calculate the enthalpy change.

Once we have those values, we can substitute them into the formula to find the answer.

Without the specific bond dissociation energies, we cannot determine whether the enthalpy change is +1520 kJ/mol, -1520 kJ/mol, +120 kJ/mol, or -120 kJ/mol.

This problem has been solved

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