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During cellular respiration one molecule of glucose is first broken down into two molecules ofAcetic acidPyruvic acidLactic acidNone of the above

Question

During cellular respiration one molecule of glucose is first broken down into two molecules ofAcetic acidPyruvic acidLactic acidNone of the above

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Solution

During cellular respiration, one molecule of glucose is first broken down into two molecules of Pyruvic acid.

Here are the steps:

  1. Glycolysis: This is the first step in cellular respiration. One molecule of glucose (which has six carbons) is broken down into two molecules of pyruvic acid (each has three carbons). This process occurs in the cytoplasm and does not require oxygen.

  2. Transition Reaction: Each pyruvic acid is then converted into Acetyl CoA which will enter the Krebs cycle. This step also occurs in the mitochondria.

  3. Krebs Cycle: The Acetyl CoA is broken down and energy is transferred to energy-carrying molecules. This step occurs in the mitochondria.

  4. Electron Transport Chain: The energy-carrying molecules from the Krebs cycle transfer their energy to other molecules which use it to produce ATP. This step occurs in the mitochondria and requires oxygen.

So, the correct answer is Pyruvic acid.

This problem has been solved

Similar Questions

Glycolysis is a part of cellular respiration that breaks the glucose molecule down to what? A. Acetyl CoA B. Pyruvic acid C. FADH2 D. ATP and NADH

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Which of the following is NOT true about a one molecule of glucose in cellular respiration?Group of answer choicesproduces 36 ATP after three steps are completedrequires that the Kreb Cycle be done twiceproduces many NADPH as electron carrierswas created from the breakdown of carbohydrates in digestionall of the above

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Name the end product and the intermediate product of glucosebreakdown in aerobic respiration?

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