Sid had scored 16 less marks in the test he would have scored exactly double the marksthat Susan scored in the test. The marks of Sid and Susan combined equals 421What were the marks scored by Sid in the test?(A) 135(B) 270(C) 286(D) 298(E) 34
Question
Sid had scored 16 less marks in the test he would have scored exactly double the marksthat Susan scored in the test. The marks of Sid and Susan combined equals 421What were the marks scored by Sid in the test?(A) 135(B) 270(C) 286(D) 298(E) 34
Solution
Let's denote the marks scored by Sid as S and the marks scored by Susan as s.
From the problem, we know that:
-
S + s = 421 (the combined score of Sid and Susan)
-
S - 16 = 2s (if Sid scored 16 less, he would have exactly double the marks that Susan scored)
We can solve these two equations to find the values of S and s.
First, rearrange the second equation to express S in terms of s: S = 2s + 16
Then, substitute this into the first equation: 2s + 16 + s = 421
Combine like terms: 3s + 16 = 421
Subtract 16 from both sides: 3s = 405
Finally, divide by 3 to solve for s: s = 135
Substitute s = 135 into the first equation to find S: S = 421 - 135 = 286
So, Sid scored 286 marks in the test. The answer is (C) 286.
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