The given Boolean function Y = CD + EF + G can be realized using 2 AND gates and 3 OR gates. Here's how:

Step 1: Realize the AND operations
The AND operations are CD and EF. Each of these operations requires one AND gate. So, we need 2 AND gates for this.

Step 2: Realize the OR operations
The OR operations are between (CD), (EF), and G. Each of these operations requires one OR gate. So, we need 3 OR gates for this.

So, the answer is 2 AND gates and 3 OR gates, which corresponds to option a.2,3.

Question

The given Boolean function Y = CD + EF + G can be realized using 2 AND gates and 3 OR gates. Here's how:

Step 1: Realize the AND operations
The AND operations are CD and EF. Each of these operations requires one AND gate. So, we need 2 AND gates for this.

Step 2: Realize the OR operations
The OR operations are between (CD), (EF), and G. Each of these operations requires one OR gate. So, we need 3 OR gates for this.

So, the answer is 2 AND gates and 3 OR gates, which corresponds to option a.2,3.

Knowee AI · Accepted Answer

The given Boolean function Y = CD + EF + G can be realized using 2 AND gates and 3 OR gates. Here's how:

Step 1: Realize the AND operations
The AND operations are CD and EF. Each of these operations requires one AND gate. So, we need 2 AND gates for this.

Step 2: Realize the OR operations
The OR operations are between (CD), (EF), and G. Each of these operations requires one OR gate. So, we need 3 OR gates for this.

So, the answer is 2 AND gates and 3 OR gates, which corresponds to option a.2,3.

How many two-input AND and OR gates are required to realize Y = CD+EF+G?a.2,3b.2,2c.3,3d.3,2

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