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Given an integer n, return true if it is a power of three. Otherwise, return false.An integer n is a power of three, if there exists an integer x such that n == 3x.

Question

Given an integer n, return true if it is a power of three. Otherwise, return false.An integer n is a power of three, if there exists an integer x such that n == 3x.

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Solution

Here is a step-by-step solution in Python:

  1. First, we need to handle the special case where n is less than or equal to 0. In this case, we return False because a power of three cannot be less than or equal to 0.
if n <= 0:
    return False
  1. Next, we check if n is a power of three. We can do this by repeatedly dividing n by 3 as long as it is divisible by 3. If n is a power of three, we will eventually get 1.
while n % 3 == 0:
    n /= 3
  1. Finally, we check if n is 1. If it is, that means n is a power of three. Otherwise, it is not.
return n == 1

Here is the complete function:

def isPowerOfThree(n):
    if n <= 0:
        return False
    while n % 3 == 0:
        n /= 3
    return n == 1

This function will return True if n is a power of three and False otherwise.

This problem has been solved

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