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When 100 cm3 of 1.0 moldm−3 HCl is mixed with 100 cm3 of 1.0 moldm−3 NaOH, the temperature of the resulting solution increases by 5.0 °C. What will be the temperature change, in °C, when 50 cm3 of these two solutions are mixed?A.     2.5B.     5.0C.     10D.     20

Question

When 100 cm3 of 1.0 moldm−3 HCl is mixed with 100 cm3 of 1.0 moldm−3 NaOH, the temperature of the resulting solution increases by 5.0 °C. What will be the temperature change, in °C, when 50 cm3 of these two solutions are mixed?A.     2.5B.     5.0C.     10D.     20

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Solution

The temperature change is directly proportional to the amount of reactants used in the reaction. In this case, the volume of the reactants is halved from 100 cm3 to 50 cm3, so the temperature change will also be halved. Therefore, the temperature change when 50 cm3 of these two solutions are mixed will be 5.0 °C / 2 = 2.5 °C. So, the answer is A. 2.5.

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