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What order do the keys print in after the following code is run?counts = {'annie' : 42, 'chuck' : 1, 'jan' : 100}items = counts.items()sorted(items, key = lambda t: t[1])for item in items: print(item[0]) jan, chuck, annie chuck, annie, janannie, chuck, janjan, annie, chuck

Question

What order do the keys print in after the following code is run?counts = {'annie' : 42, 'chuck' : 1, 'jan' : 100}items = counts.items()sorted(items, key = lambda t: t[1])for item in items: print(item[0]) jan, chuck, annie chuck, annie, janannie, chuck, janjan, annie, chuck

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Solution

The keys will print in the order they were originally added to the dictionary, which is 'annie', 'chuck', 'jan'. This is because dictionaries in Python are ordered collections since version 3.7.

Here's the step by step explanation:

  1. The dictionary counts is created with keys 'annie', 'chuck', and 'jan' and corresponding values 42, 1, and 100.

  2. The items() method is called on counts which returns a view object that displays a list of a dictionary's key-value tuple pairs. This is assigned to the variable items.

  3. The sorted() function is called with items as the argument and a lambda function as the key which sorts the items by their values. However, this sorted list is not assigned to any variable, so it is not used in the following code.

  4. A for loop is used to iterate over items and print the keys. Since items was not updated after being sorted, the keys are printed in the order they were originally added to the dictionary.

So, the output will be:

annie
chuck
jan

This problem has been solved

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