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Andy wants to examine the impact of years of education (EDUC) and labour productivity(PROD) on monthly salary (SALARY) of a sample of 150 teachers at StellenboschMunicipality. However, it is difficult to measure productivity. Hence, it is approximated asfollows: PROD = Pupil/Teacher ratio of the school where the teacher works. In other words,the regression model is:).,( PRODEDUCfSALARY = Andy argues that various reasonslead to the presence of error terms in the above regression. Explain any five of these reasons.Always refer to the above regression in your explanationQUESTION 2Busisiwe would like to investigate the relationship between weekly party hours (PARTY) andmodule test marks (MARKS) of a sample of 12 second-year Microeconomics students. Theinformation is presented in the following table:Student PARTY (X) MARKS (Y)[A] 02 90[B] 03 85[C] 04 82[D] 04 76[E] 04 75[F] 05 74[G] 05 70[H] 06 62[I] 07 55[J] 08 52[K] 10 43[L] 14 402.1 Complete the following table with the aid of the data in the above table: XYXY XY 2X5562.2 By using the OLS method to derive the parameters of the bivariate regression:.^2^1^PARTYMARKS +=Show all calculations.Hints:22^2XnXYXnYXiii−−=XY ^2^1−=

Question

Andy wants to examine the impact of years of education (EDUC) and labour productivity(PROD) on monthly salary (SALARY) of a sample of 150 teachers at StellenboschMunicipality. However, it is difficult to measure productivity. Hence, it is approximated asfollows: PROD = Pupil/Teacher ratio of the school where the teacher works. In other words,the regression model is:).,( PRODEDUCfSALARY = Andy argues that various reasonslead to the presence of error terms in the above regression. Explain any five of these reasons.Always refer to the above regression in your explanationQUESTION 2Busisiwe would like to investigate the relationship between weekly party hours (PARTY) andmodule test marks (MARKS) of a sample of 12 second-year Microeconomics students. Theinformation is presented in the following table:Student PARTY (X) MARKS (Y)[A] 02 90[B] 03 85[C] 04 82[D] 04 76[E] 04 75[F] 05 74[G] 05 70[H] 06 62[I] 07 55[J] 08 52[K] 10 43[L] 14 402.1 Complete the following table with the aid of the data in the above table: XYXY XY 2X5562.2 By using the OLS method to derive the parameters of the bivariate regression:.^2^1^PARTYMARKS +=Show all calculations.Hints:22^2XnXYXnYXiii−−=XY ^2^1−=

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Solution

The first part of your question is asking for reasons why there might be error terms in the regression model that Andy is using to examine the impact of years of education and labour productivity on monthly salary. Here are five possible reasons:

  1. Measurement Error: This could occur if there is any inaccuracy in the measurement of the variables. For example, the productivity measure (Pupil/Teacher ratio) might not accurately reflect a teacher's productivity.

  2. Omitted Variable Bias: This occurs when a variable that influences the dependent variable is not included in the model. For example, the model does not account for factors like teaching experience or the teacher's level of qualification, which could also affect their salary.

  3. Specification Error: This happens when the functional form of the model is incorrectly specified. For example, the relationship between the variables might not be linear as assumed in the model.

  4. Sample Selection Bias: This could occur if the sample of teachers is not representative of the population of all teachers in the Stellenbosch Municipality.

  5. Random Variation: This is the inherent randomness in any process, which can lead to differences between the observed outcomes and the outcomes predicted by the model.

For the second part of your question, you are asked to complete a table and use the Ordinary Least Squares (OLS) method to derive the parameters of a bivariate regression. Here's how you can do it:

First, you need to calculate the sum of X (PARTY), the sum of Y (MARKS), the sum of XY, and the sum of X squared.

Then, you can use these sums to calculate the parameters of the regression using the formulas provided.

The formula for beta1 (β1) is: (nΣXY - ΣXΣY) / (nΣX^2 - (ΣX)^2)

The formula for beta2 (β2) is: ΣY/n - β1(ΣX/n)

Where n is the number of observations (in this case, 12 students), ΣX is the sum of X, ΣY is the sum of Y, and ΣXY is the sum of the product of X and Y.

Please note that you need to have the actual data to perform these calculations.

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Similar Questions

In this exercise we examine which factors might influence the wages of employees. To do so, the variable wage is regressed on the variables educ, tenure, tensq, female, married, and m_female.Table 1: Descriptive StatisticsVariable Explanationwage Average hourly wage (in €)educ Years of educationtenure Employment duration (current employer)tensq = tenure × tenurefemale dummy (= 1 if female)married dummy (= 1 if married)m_female      Interaction term (= married × female)The corresponding Stata output is:Source | SS df MS N. of obs. = 526 + F(6, 519) = 57.23 Model | 2851.181 6 475.197 Prob > F = 0.000 Residual | 4309.233 519 8.303 R-squared = 0.398 + Adj. R-sq. = 0.391 Total | 7160.414 525 13.639 Root MSE = 2.882 wage | Coef. S. Err. t-stat. P > |t| [95% Conf. Int.] + educ |0.522 0.046 ? ? ? ? tenure | 0.263 0.046 5.69 0.000 0.172 0.354 tensq | -0.005 0.002 -2.77 0.006 -0.008 -0.001 female | -0.321 0.408 -0.79 0.431 -1.123 0.480 married | 1.807 0.389 4.65 0.000 1.043 2.571 m_female | -2.326 0.526 ? ? ? ? _cons | -2.012 0.662 -3.04 0.002 -3.313 -0.711 Reference: Wooldridge, J. (2013). Introductory Econometrics, 5E. © 2013 South-Western, a part of Cengage, Inc. Reproduced by permission. www.cengage.com/permissions.Does educ have a significant relationship with the outcome wage? State the associated null hypothesis and alternative hypothesis for the coefficient βeduc. Also, determine its statistical significance at the 5 percent significance level in a two-sided test. Which one is the correct answer?Answer 1H0:   vs.   H1: c(0.05, 526-6-1) = 1.645⇒ t > c⇒ H0 can be rejected at the 5 percent significance level.Answer 2H0:   vs.   H1: c(0.05, 526-6-1) = 1.645⇒ t > c⇒ H0 can be rejected at the 5 percent significance level.Answer 3H0:   vs.   H1: c(0.05, 526-6-1) = 1.960⇒ t > c⇒ H0 can be rejected at the 5 percent significance level.Answer 4H0:   vs.   H1: c(0.05, 526-6-1) = 1.960⇒ t > c⇒ H0 can be rejected at the 5 percent significance level.

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