find something that can help me solve the answer for An endothermic reaction has an activation energy of 95 kJ in the forward direction and an activation energy of 55 kJ in the reverse direction. Sketch the potential energy diagram and label the EA(Forward) , EA(Reverse) and determine and label the △HReverse. (5 marks)

For the following reaction mechanism use the diagram below to answer each question (5 marks) 16. The overall reaction in the forward direction is endothermic OR exothermic. (circle one) 17. The 2nd step of the reaction mechanism in the forward direction is endothermic OR exothermic. (circle one) 18. _________________ is the reaction intermediate. 19. The ΔH for the overall reaction in the forward direction is ________ kJ. (state the value) 20. The slowest step in the forward direction is step 1 OR step 2. (circle one) Ep (kJ) Reaction Progress

An endothermic reaction, A→ B has an activation energy 15 kcal/mol and energy of the reaction is 5 kcal/mol. The activation energy of the reaction, B → A is:

To solve this problem, you need to understand the concepts of activation energy and enthalpy change in a chemical reaction. Here are the steps: 1. Draw the potential energy diagram: This is a graph that shows the energy of the reactants and products during a chemical reaction. The y-axis represents the energy and the x-axis represents the progress of the reaction. 2. Label the activation energy for the forward reaction (EA Forward): This is the energy required to start the reaction. It is represented by the difference in energy between the reactants and the highest point on the graph (the transition state). Since the problem states that the activation energy for the forward reaction is 95 kJ, you would draw a line from the energy level of the reactants to a point on the y-axis that is 95 kJ higher, and label this line "EA Forward". 3. Label the activation energy for the reverse reaction (EA Reverse): This is the energy required to reverse the reaction. It is represented by the difference in energy between the products and the highest point on the graph. Since the problem states that the activation energy for the reverse reaction is 55 kJ, you would draw a line from the energy level of the products to the same point on the y-axis that you used for the forward reaction, and label this line "EA Reverse". 4. Determine and label the enthalpy change for the reverse reaction (ΔH Reverse): This is the difference in energy between the products and the reactants. Since the reaction is endothermic, the products have more energy than the reactants, so ΔH Reverse is positive. You can calculate it by subtracting the activation energy for the forward reaction from the activation energy for the reverse reaction (55 kJ - 95 kJ = -40 kJ). You would then draw a line from the energy level of the reactants to the energy level of the products, and label this line "ΔH Reverse = -40 kJ". Remember, this is a simplified explanation and the actual diagram might look a bit different depending on the specific reaction and the scale of the graph. ####

The activation energy for the forward reaction X Y is 60 KJ mol−1 and ΔH is −20 KJ mol−1. The activation energy for the backward reaction Y X is:

ΔH for the following reaction is -180 kJ. Is this reaction endothermic or exothermic? 2 Na(s) + 2 H2O(l) –> 2 NaOH(aq) + H2(g) Group of answer choicesendothermicexothermic