The product of two irrational numbers is not always an irrational number. For example, the square root of 2 is an irrational number. However, if you multiply the square root of 2 by itself, you get 2, which is a rational number. Therefore, the statement (A) is incorrect.

The product of two irrational numbers is also not always a rational number. For example, if you multiply the square root of 2 by the square root of 3, you get the square root of 6, which is an irrational number. Therefore, the statement (B) is incorrect.

The product of two irrational numbers is also not always an integer. Using the previous example, the square root of 6 is not an integer. Therefore, the statement (C) is incorrect.

So, none of the given options (A, B, C) are always true when multiplying two irrational numbers.

Question

The product of two irrational numbers is not always an irrational number. For example, the square root of 2 is an irrational number. However, if you multiply the square root of 2 by itself, you get 2, which is a rational number. Therefore, the statement (A) is incorrect.

The product of two irrational numbers is also not always a rational number. For example, if you multiply the square root of 2 by the square root of 3, you get the square root of 6, which is an irrational number. Therefore, the statement (B) is incorrect.

The product of two irrational numbers is also not always an integer. Using the previous example, the square root of 6 is not an integer. Therefore, the statement (C) is incorrect.

So, none of the given options (A, B, C) are always true when multiplying two irrational numbers.

Knowee AI · Accepted Answer

The product of two irrational numbers is not always an irrational number. For example, the square root of 2 is an irrational number. However, if you multiply the square root of 2 by itself, you get 2, which is a rational number. Therefore, the statement (A) is incorrect.

The product of two irrational numbers is also not always a rational number. For example, if you multiply the square root of 2 by the square root of 3, you get the square root of 6, which is an irrational number. Therefore, the statement (B) is incorrect.

The product of two irrational numbers is also not always an integer. Using the previous example, the square root of 6 is not an integer. Therefore, the statement (C) is incorrect.

So, none of the given options (A, B, C) are always true when multiplying two irrational numbers.

The product of any two irrational numbers is(A) always an irrational number(B) always a rational number(C) always an integer

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