What value do we need to load the timer’s register if we want to have a time delay of 5 ms (milliseconds) using timer 0, T0 in mode 1? Consider crystal frequency to be 12 MHz.1 pointTH0 = CEH, TL0 = 70HTL0 = ECH, TH0 = 78Hnone of theseTH0 = ECH, TL0 = 78H

To solve this problem, we first need to understand the timer configuration and how it works in the microcontroller.

In mode 1, Timer 0 (T0) is a 16-bit timer, which means it can count from 0x0000 to 0xFFFF (65535 in decimal).

The time delay generated by the timer is determined by the crystal frequency. In this case, the crystal frequency is 12 MHz.

The time for one machine cycle = 1 / (Crystal Frequency / 12) = 1 / (12 MHz / 12) = 1 / 1 MHz = 1 µs (microsecond)

So, the timer will increment by 1 every 1 µs.

If we want a delay of 5 ms (or 5000 µs), the timer will need to count to 5000.

However, since the timer can only count to 65535, we need to preload the timer with a value that will cause it to overflow after it has counted to 5000.

This preload value is calculated as follows:

Preload Value = Timer Max Value - Required Count + 1 = 65535 - 5000 + 1 = 60536

This value needs to be loaded into the timer's register as a 16-bit value. In hexadecimal, 60536 is 0xEC78.

Therefore, TH0 should be loaded with 0xEC and TL0 should be loaded with