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For example if  α, β, γ  are roots of  ax3 + bx2 + cx + d  =  0 to find equation whose roots are  1/α, 1/β, 1/γ, we put  1α  =  y  ⇒  α  =  1y . As  α  is a root of  ax3 + bx2 + cx + d  =  0, we get  ay3 + by2 + cy + d  =  0  or  a + by + cy2 + dy3  =  0 This is the desired equation.The same result holds for all polynomial equations.If  α, β  are roots of  ax2 + bx + c  =  0  the roots of  a(x − 1)2 + b(x − 1)(x − 2) + c(x − 2)2  =  0  are

Question

For example if  α, β, γ  are roots of  ax3 + bx2 + cx + d  =  0 to find equation whose roots are  1/α, 1/β, 1/γ, we put  1α  =  y  ⇒  α  =  1y . As  α  is a root of  ax3 + bx2 + cx + d  =  0, we get  ay3 + by2 + cy + d  =  0  or  a + by + cy2 + dy3  =  0 This is the desired equation.The same result holds for all polynomial equations.If  α, β  are roots of  ax2 + bx + c  =  0  the roots of  a(x − 1)2 + b(x − 1)(x − 2) + c(x − 2)2  =  0  are

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Solution

The roots of the equation a(x - 1)² + b(x - 1)(x - 2) + c(x - 2)² = 0 are α + 1 and β + 2. This is because the transformation x → x - 1 shifts the roots of the equation ax² + bx + c = 0 by 1 to the right, and the transformation x → x - 2 shifts the roots of the equation ax² + bx + c = 0 by 2 to the right. Therefore, the roots of the transformed equation are the original roots shifted by 1 and 2, respectively.

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