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#include<stdio.h>int main(){int a;scanf("%d",&a);int B=a%2;int C=a*a*a;int D=a*a;switch(B){case 0:printf("Even\n");printf("%d\n",C);break;case 1:printf("Odd\n");printf("%d\n",D);break;}return 0;}

Question

#include<stdio.h>int main(){int a;scanf("%d",&a);int B=a%2;int C=aaa;int D=a*a;switch(B){case 0:printf("Even\n");printf("%d\n",C);break;case 1:printf("Odd\n");printf("%d\n",D);break;}return 0;}

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Solution

This is a C program that takes an integer as input and checks whether it is even or odd. If the number is even, it prints "Even" and the cube of the number. If the number is odd, it prints "Odd" and the square of the number.

Here is a step-by-step explanation:

  1. The program starts with the inclusion of the standard input-output header file #include<stdio.h>.

  2. The main() function is declared, which is the entry point of the program.

  3. Inside the main() function, an integer a is declared.

  4. The scanf() function is used to take the input from the user and store it in the variable a.

  5. The modulus operator % is used to find the remainder of a when divided by 2. The result is stored in the variable B. If a is even, B will be 0. If a is odd, B will be 1.

  6. The cube of a is calculated and stored in the variable C.

  7. The square of a is calculated and stored in the variable D.

  8. A switch statement is used to check the value of B.

  9. If B is 0 (which means a is even), it prints "Even" and the value of C (which is the cube of a).

  10. If B is 1 (which means a is odd), it prints "Odd" and the value of D (which is the square of a).

  11. The program ends with return 0; which indicates successful termination of the program.

This problem has been solved

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