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The electric field associated with an EM wave in vacuum is given by E =40 cos (kz−6 ×108 t) ˆi, where E, z and t are in V/m, meter and seconds respectively. The value of wave vector k is

Question

The electric field associated with an EM wave in vacuum is given by E =40 cos (kz−6 ×108 t) ˆi, where E, z and t are in V/m, meter and seconds respectively. The value of wave vector k is

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Solution

The wave vector k in the given equation for the electric field E = 40 cos (kz - 6 × 10^8 t) can be found by comparing it to the general form of the wave equation E = E0 cos (kz - wt), where E0 is the amplitude, k is the wave vector, w is the angular frequency, and t is time.

In the given equation, we don't have a direct value for k. However, we can see that the term with z is kz. This means that k is the coefficient of z in the argument of the cosine function.

Unfortunately, without additional information or context, we cannot determine a specific numerical value for k. We need more information about the wave, such as its wavelength or frequency, to calculate k.

In general, the wave vector k is related to the wavelength λ by the equation k = 2π/λ. If we know the wavelength of the wave, we can substitute it into this equation to find k. Similarly, if we know the frequency of the wave, we can use the equation k = w/c, where c is the speed of light, to find k.

In conclusion, without additional information about the wave, we cannot determine a specific numerical value for the wave vector k.

This problem has been solved

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