Without the diagram, it's difficult to provide a precise answer. However, I can give a general explanation.

The force between two charges is given by Coulomb's law:

F = k * |q1*q2| / r^2

where:
F is the force,
k is Coulomb's constant (8.99 x 10^9 N m^2/C^2),
q1 and q2 are the charges, and
r is the distance between the charges.

The direction of the force depends on the signs of the charges. Like charges repel each other, and opposite charges attract each other.

Since Q is a positive charge, it will be repelled by other positive charges and attracted to negative charges. Therefore, Q will be repelled by Q1 and Q3 (which are both positive) and attracted to Q2 (which is negative).

So, the resultant force on Q will be a combination of these forces. Without knowing the exact positions of the charges, it's impossible to say for certain what the resultant force will be. However, since Q2 has the largest magnitude and is opposite in sign to Q, it's likely that the resultant force on Q will be directed towards Q2.

So, the most likely answer is (c) Directed towards q2. But again, without the diagram, this is just an educated guess.

Question

Without the diagram, it's difficult to provide a precise answer. However, I can give a general explanation.

The force between two charges is given by Coulomb's law:

F = k * |q1*q2| / r^2

where:
F is the force,
k is Coulomb's constant (8.99 x 10^9 N m^2/C^2),
q1 and q2 are the charges, and
r is the distance between the charges.

The direction of the force depends on the signs of the charges. Like charges repel each other, and opposite charges attract each other.

Since Q is a positive charge, it will be repelled by other positive charges and attracted to negative charges. Therefore, Q will be repelled by Q1 and Q3 (which are both positive) and attracted to Q2 (which is negative).

So, the resultant force on Q will be a combination of these forces. Without knowing the exact positions of the charges, it's impossible to say for certain what the resultant force will be. However, since Q2 has the largest magnitude and is opposite in sign to Q, it's likely that the resultant force on Q will be directed towards Q2.

So, the most likely answer is (c) Directed towards q2. But again, without the diagram, this is just an educated guess.

Knowee AI · Accepted Answer

Without the diagram, it's difficult to provide a precise answer. However, I can give a general explanation.

The force between two charges is given by Coulomb's law:

F = k * |q1*q2| / r^2

where:
F is the force,
k is Coulomb's constant (8.99 x 10^9 N m^2/C^2),
q1 and q2 are the charges, and
r is the distance between the charges.

The direction of the force depends on the signs of the charges. Like charges repel each other, and opposite charges attract each other.

Since Q is a positive charge, it will be repelled by other positive charges and attracted to negative charges. Therefore, Q will be repelled by Q1 and Q3 (which are both positive) and attracted to Q2 (which is negative).

So, the resultant force on Q will be a combination of these forces. Without knowing the exact positions of the charges, it's impossible to say for certain what the resultant force will be. However, since Q2 has the largest magnitude and is opposite in sign to Q, it's likely that the resultant force on Q will be directed towards Q2.

So, the most likely answer is (c) Directed towards q2. But again, without the diagram, this is just an educated guess.

Question

Solution

Similar Questions

Upgrade your grade with Knowee