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1. How exhaustive search method uses Brute force approach to evaluate various problems and find whether the given string follows the specified pattern and return 0 or 1 accordingly. Examples: Pattern “abba” input: “redblueredblue” should return 1 Pattern “aaaa” input: ”asdasdasdasd” should return 1 Pattern “aabb” input: “xyzabcxyzabc” ” should return 0

Question

  1. How exhaustive search method uses Brute force approach to evaluate various problems and find whether the given string follows the specified pattern and return 0 or 1 accordingly. Examples: Pattern “abba” input: “redblueredblue” should return 1 Pattern “aaaa” input: ”asdasdasdasd” should return 1 Pattern “aabb” input: “xyzabcxyzabc” ” should return 0
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Solution

The exhaustive search method, also known as the brute force method, is a general problem-solving technique that explores all possible solutions to a problem. This method is used when the solution space is small, or when there is no better algorithm available.

Here's how it can be used to evaluate whether a given string follows a specified pattern:

  1. First, we need to define the pattern and the string. The pattern is a sequence of characters (like "abba" or "aaaa") and the string is the text we want to check against this pattern (like "redblueredblue" or "asdasdasdasd").

  2. Next, we start at the beginning of the string and try to match the first character of the pattern with the first character of the string. If they match, we move on to the next character in both the pattern and the string.

  3. We continue this process until we have either matched all characters in the pattern with characters in the string, or we find a character that does not match. If all characters match, we return 1, indicating that the string follows the pattern. If we find a character that does not match, we return 0, indicating that the string does not follow the pattern.

  4. If the pattern is shorter than the string, we repeat the process with the remaining characters in the string.

For example, with the pattern "abba" and the string "redblueredblue", we can see that "red" corresponds to "a" and "blue" corresponds to "b". Since the pattern is repeated in the string, we return 1.

With the pattern "aaaa" and the string "asdasdasdasd", we can see that "asd" corresponds to "a". Since the pattern is repeated in the string, we return 1.

With the pattern "aabb" and the string "xyzabcxyzabc", we can see that "xyz" corresponds to "a" and "abc" corresponds to "b". However, the pattern is not repeated in the string, so we return 0.

This problem has been solved

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