Roel can paint a room in 5 hours and Vergel can do it in 6 hours. What part of the job can they do by working for 2hours?
Question
Roel can paint a room in 5 hours and Vergel can do it in 6 hours. What part of the job can they do by working for 2hours?
Solution 1
To solve this problem, we first need to determine how much of the room each person can paint per hour.
- Roel can paint a room in 5 hours, so he can paint 1/5 of the room in one hour.
- Vergel can paint a room in 6 hours, so he can paint 1/6 of the room in one hour.
When they work together, we can add up the fractions of the room they can paint per hour.
1/5 + 1/6 = 11/30
This means that together, they can paint 11/30 of the room in one hour.
If they work for 2 hours, we multiply this rate by 2:
2 * 11/30 = 22/30 = 0.73
So, Roel and Vergel can paint approximately 73% of the room by working together for 2 hours.
Solution 2
Sure, let's break it down:
-
Roel can paint a room in 5 hours. This means in one hour, Roel can paint 1/5 of the room.
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Vergel can paint a room in 6 hours. This means in one hour, Vergel can paint 1/6 of the room.
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When they work together, their combined rate is the sum of their individual rates. So in one hour, they can paint 1/5 + 1/6 = 11/30 of the room.
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If they work together for 2 hours, they can paint 2 * (11/30) = 22/30 = 0.73 (rounded to two decimal places) of the room.
So, Roel and Vergel can paint approximately 73% of the room by working together for 2 hours.
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