If you needed to randomly select one friend out of your 5 best friends to go to the football with you, a method to simulate this would be:
Question
If you needed to randomly select one friend out of your 5 best friends to go to the football with you, a method to simulate this would be:
Solution
- Write each of your 5 best friends' names on a separate piece of paper.
- Fold each piece of paper so the names are not visible.
- Place all the folded pieces of paper in a hat or a bowl.
- Mix the pieces of paper around so you don't know which one you're picking.
- Without looking, draw one piece of paper from the hat or bowl.
- The name on the piece of paper you draw is the friend you will invite to the football game. This method ensures each friend has an equal chance of being selected.
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Alice, Bob, Ben, and some of their friends participated in a competition. They were standing in line to take the participation ticket. Each person was given a unique ticket value which has a rating. You need to implement a code to form a team of 3 friends amongst them under the given rules:Select 3 friends with index(a,b,c) with ticket value(ticket[a], ticket[b], ticket[c].Team is valid only if(ticket[a] < ticket[b] < ticket [c] OR ticket[a] > ticket[b] > ticket [c] where,(0<=a<=b<=c<=n) (n=number of students participated)Complete the below pseudocode:Pseudocode:Function numTeams{Input int ticket, int Result = 0;for(int mid = 1; mid< ticket.length -1;mid++){int left=0;int right =0;int upperleft=0;int upperright =0;for(int b=0;b<ticket.length;b++) { if(b<mid and ticket[b]< ticket[mid]){ left+=1; } else if(b>mid and ticket[b] > ticket[mid]) { right+=1; } //code line 18 { upperleft+=1; } else if(b>mid and ticket[b] < ticket[mid]) { upperright+=1; }}Result+= left * right;//code line 28}return Result;}What will be the code in place of lines 18 and 28?Options:else if(b>mid and ticket[b]> ticket[mid]) //line 18Result+= upperleft+ upperleft* upperright; //line 28else if(b<ticket[mid] and ticket[b]< ticket[mid]) //line 18Result+= upperleft + upperright * upperleft; //line 28else if(b<mid and ticket[b]< ticket[mid]) //line 18Result+= upperleft + upperright; //line 28else if(b<mid and ticket[b]> ticket[mid]) //line 18Result+= upperleft * upperright; //line 28
can you make a program of game which tells the score when given a choice like a and b where a and b are famous celebrities or influencers. we have to guess out of a and b which has more followers. a and b are randomly generated from already prepared people list which has there name, follower count, description and country (we must display name, description and country). the game continues until a wrong choice is guessed. with every guess it must ask the user again to guess who has more instagram followers and clear the screen after the answer is given untill the user enters the wrong answer the screen must be cleared and said sorry you lost and print there score final . i will provide the peoples list
Question3Max. score: 4.00Alice, Bob, Ben, and some of their friends participated in a competition. They were standing in line to take the participation ticket. Each person was given a unique ticket value which has a rating. You need to implement a code to form a team of 3 friends amongst them under the given rules:Select 3 friends with index(a,b,c) with ticket value(ticket[a], ticket[b], ticket[c].Team is valid only if(ticket[a] < ticket[b] < ticket [c] OR ticket[a] > ticket[b] > ticket [c] where,(0<=a<=b<=c<=n) (n=number of students participated)Complete the below pseudocode:Pseudocode:Function numTeams{Input int ticket, int Result = 0;for(int mid = 1; mid< ticket.length -1;mid++){int left=0;int right =0;int upperleft=0;int upperright =0;for(int b=0;b<ticket.length;b++) { if(b<mid and ticket[b]< ticket[mid]){ left+=1; } else if(b>mid and ticket[b] > ticket[mid]) { right+=1; } //code line 18 { upperleft+=1; } else if(b>mid and ticket[b] < ticket[mid]) { upperright+=1; }}Result+= left * right;//code line 28}return Result;}What will be the code in place of lines 18 and 28?Options:else if(b>mid and ticket[b]> ticket[mid]) //line 18Result+= upperleft+ upperleft* upperright; //line 28else if(b<ticket[mid] and ticket[b]< ticket[mid]) //line 18Result+= upperleft + upperright * upperleft; //line 28else if(b<mid and ticket[b]< ticket[mid]) //line 18Result+= upperleft + upperright; //line 28else if(b<mid and ticket[b]> ticket[mid]) //line 18Result+= upperleft * upperright; //line 281234
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