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number if ‘i’ is a factor ‘n’. Given two lists of numbers l1 and l2 form a list l3 by inserting factor indexed numbers of l1 and l2. Intialize index to ‘0’ visit elements of l1 and l2 at index, if one of them is factored indexed insert and increment index and go till end of the list. If both of them are factor indexed then insert element of l1 at index and then element of l2 at index and increment index. If end of one of the list is reached then add elements of other list to l3 if they are factor indexed. After construction of l3, Print the numbers which continues to be factor indexed in l3.

Question

number if ‘i’ is a factor ‘n’. Given two lists of numbers l1 and l2 form a list l3 by inserting factor indexed numbers of l1 and l2. Intialize index to ‘0’ visit elements of l1 and l2 at index, if one of them is factored indexed insert and increment index and go till end of the list. If both of them are factor indexed then insert element of l1 at index and then element of l2 at index and increment index. If end of one of the list is reached then add elements of other list to l3 if they are factor indexed. After construction of l3, Print the numbers which continues to be factor indexed in l3.

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Solution

To answer the given question, we need to perform the following steps:

  1. Initialize a list, l3, to store the factor indexed numbers from l1 and l2.
  2. Set the index variable to 0.
  3. Iterate through the elements of l1 and l2 simultaneously, accessing elements at the current index.
  4. If either l1 or l2 has a factor indexed number at the current index, insert that number into l3 and increment the index.
  5. If both l1 and l2 have factor indexed numbers at the current index, insert the element from l1 into l3 at the current index, then insert the element from l2 at the same index, and increment the index.
  6. If we reach the end of one of the lists, add the remaining factor indexed elements from the other list to l3.
  7. After constructing l3, print the numbers that continue to be factor indexed in l3.

Please note that the specific implementation details may vary depending on the programming language being used.

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Similar Questions

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