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Consider the Python Listarr = [[123],[456]]What will the following code display?for i in range(len(rows)):   for j in range(len(columns)):      print(rows[i][j],end=" ")print("\n") Group of answer choices1 2 3 4 5 6123456None of the option given

Question

Consider the Python Listarr = [[123],[456]]What will the following code display?for i in range(len(rows)):   for j in range(len(columns)):      print(rows[i][j],end=" ")print("\n") Group of answer choices1 2 3 4 5 6123456None of the option given

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Solution

The code you provided seems to have some errors. It refers to 'rows' and 'columns' which are not defined anywhere. If we assume that 'rows' is 'arr' and 'columns' is the length of the sublists in 'arr', the code should look like this:

arr = [[123],[456]]
for i in range(len(arr)):
   for j in range(len(arr[i])):
      print(arr[i][j],end=" ")
print("\n")

However, this will print '123 456', not '1 2 3 4 5 6' or '123456'. If you want to print each digit separately, you need to convert the numbers to strings first and iterate over the characters. Here is how you can do it:

arr = [[123],[456]]
for i in range(len(arr)):
   for j in range(len(arr[i])):
      for digit in str(arr[i][j]):
         print(digit,end=" ")
print("\n")

This will print '1 2 3 4 5 6'.

This problem has been solved

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