What is the functionality of the following code?Public void function(node node) { if(size == 0) head = node; else { node temp,cur; for(cur = head; (Temp = cur.Getnext())!=Null; cur = temp); cur.Setnext(node); } size++; }Select one:a. Inserting a node at the beginning of the list.b. Deleting a node at the beginning of the list.c.Inserting a node at the end of the list.d.Deleting a node at the end of the list.
Question
What is the functionality of the following code?Public void function(node node) { if(size == 0) head = node; else { node temp,cur; for(cur = head; (Temp = cur.Getnext())!=Null; cur = temp); cur.Setnext(node); } size++; }Select one:a. Inserting a node at the beginning of the list.b. Deleting a node at the beginning of the list.c.Inserting a node at the end of the list.d.Deleting a node at the end of the list.
Solution
Sure, let's analyze the code step by step to determine its functionality.
Public void function(node node) {
if(size == 0)
head = node;
else {
node temp, cur;
for(cur = head; (temp = cur.Getnext()) != null; cur = temp);
cur.Setnext(node);
}
size++;
}
-
Check if the list is empty:
if(size == 0) head = node;- If the size of the list is 0, it means the list is empty.
- The new node is set as the head of the list.
-
If the list is not empty:
else { node temp, cur; for(cur = head; (temp = cur.Getnext()) != null; cur = temp); cur.Setnext(node); }- Initialize two node variables,
tempandcur. - Start from the head of the list (
cur = head). - Traverse the list until the end is reached (
(temp = cur.Getnext()) != null). - Once the end is reached, set the next pointer of the last node to the new node (
cur.Setnext(node)).
- Initialize two node variables,
-
Increment the size of the list:
size++;
Based on this analysis, the code is inserting a node at the end of the list. Therefore, the correct answer is:
c. Inserting a node at the end of the list.
Similar Questions
What does the following Python code snippet do?def delete_node(self, key): temp = self.head if temp is not None: if temp.data == key: self.head = temp.next temp = None return while temp is not None: if temp.data == key: break prev = temp temp = temp.next if temp == None: return prev.next = temp.next temp = None
What does the following Python code snippet accomplish?class LinkedList: def __init__(self): self.head = None def insert_at_beginning(self, data): new_node = Node(data) new_node.next = self.head self.head = new_nodeInserts a new node at the beginning of the linked listDeletes the last node of the linked listAppends a new node to the end of the linked listReverses the linked list
Linked List Operations: Traverse, Insert and DeleteTraversal - access each element of the linked list.Insertion - adds a new element to the linked list.Deletion - removes the existing elements.Search - find a node in the linked list.Sort - sort the nodes of the linked list.
Public void function(node node) { if(size == 0) head = node; else { node temp,cur; for(cur = head; (Temp = cur.Getnext())!=Null; cur = temp); cur.Setnext(node); } size++; }
Problem Statement23hr leftGiven a linked list, write a program to insert or delete nodes from the beginning.Input:n = 5[6, 5, 4, 3, 2, 1]Notice that here, we are inserting each element from the beginning. Hence when you insert a new element, the list becomes newEle + OldLL.For example, if you add 3 to [4, 5, 6] then it becomes [3, 4, 5, 6].Output:[1, 2, 3, 4, 5, 6] -> after inserting elements [2, 3, 4, 5, 6] -> after deleting the beginning elementConstraint:If the linked list is empty, print an empty space.
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