Using the properties of combinations of continuous functions, determine the interval(s) over whichthe function f(x) = x²-3x-18 x+2 is continuous.A. (-∞,-2)U(-2,00)B. (-2,2)C. (-8,08)D. (-0,-3)U(-3,-2)U(-2, 6) U (6,0∞)
Question
Using the properties of combinations of continuous functions, determine the interval(s) over whichthe function f(x) = x²-3x-18 x+2 is continuous.A. (-∞,-2)U(-2,00)B. (-2,2)C. (-8,08)D. (-0,-3)U(-3,-2)U(-2, 6) U (6,0∞)
Solution
The function f(x) = (x²-3x-18)/(x+2) is a rational function, which is a ratio of two polynomial functions.
Rational functions are continuous everywhere except at the points where the denominator is zero. This is because division by zero is undefined.
So, to find the interval of continuity for this function, we need to find the value of x that makes the denominator zero.
Setting the denominator equal to zero gives:
x + 2 = 0
Solving for x gives:
x = -2
So, the function is not continuous at x = -2.
Therefore, the function is continuous for all real numbers except x = -2.
In interval notation, this is (-∞, -2) U (-2, ∞).
So, the correct answer is A. (-∞,-2)U(-2,∞).
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