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Two identical balls A and B collide head on elastically. If velocities of A and B, before the collision are +0.5m/s and -0.3m/s respectively, then their velocities, after the collision, are respectively:

Question

Two identical balls A and B collide head on elastically. If velocities of A and B, before the collision are +0.5m/s and -0.3m/s respectively, then their velocities, after the collision, are respectively:

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Solution

The velocities of two identical balls after an elastic collision can be calculated using the formula for elastic collision:

v1' = ((m1 - m2) / (m1 + m2)) * v1 + ((2 * m2) / (m1 + m2)) * v2 v2' = ((2 * m1) / (m1 + m2)) * v1 - ((m1 - m2) / (m1 + m2)) * v2

where:

  • v1' and v2' are the velocities of balls A and B after the collision,
  • v1 and v2 are the velocities of balls A and B before the collision,
  • m1 and m2 are the masses of balls A and B.

Given that the balls are identical, m1 = m2. Therefore, the formulas simplify to:

v1' = v2 v2' = v1

So, the velocity of ball A after the collision will be -0.3 m/s, and the velocity of ball B after the collision will be +0.5 m/s.

This problem has been solved

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