A water sample contains the following: Ca2+=120 ppm, Mg2+=120 ppm, CO2=132 ppm, HCO3-=122 ppm and K+=40 ppm. Calculate the amount of lime 80% pure and soda 90% pure for softening of 106 litres of water.
Question
A water sample contains the following: Ca2+=120 ppm, Mg2+=120 ppm, CO2=132 ppm, HCO3-=122 ppm and K+=40 ppm. Calculate the amount of lime 80% pure and soda 90% pure for softening of 106 litres of water.
Solution
To calculate the amount of lime and soda required for softening of water, we need to consider the hardness caused by Ca2+, Mg2+, CO2, and HCO3-.
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Calculate the hardness caused by Ca2+ and Mg2+: Ca2+ hardness = 120 ppm = 120 mg/L Mg2+ hardness = 120 ppm = 120 mg/L
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Convert the hardness into CaCO3 equivalents: Ca2+ hardness as CaCO3 = 120 mg/L * (100/40) = 300 mg/L Mg2+ hardness as CaCO3 = 120 mg/L * (100/24.3) = 493.83 mg/L
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Calculate the hardness caused by CO2 and HCO3-: CO2 hardness = 132 ppm = 132 mg/L HCO3- hardness = 122 ppm = 122 mg/L
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Convert the hardness into CaCO3 equivalents: CO2 hardness as CaCO3 = 132 mg/L * (100/44) = 300 mg/L HCO3- hardness as CaCO3 = 122 mg/L * (100/61) = 200 mg/L
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Calculate the total hardness: Total hardness = Ca2+ hardness as CaCO3 + Mg2+ hardness as CaCO3 + CO2 hardness as CaCO3 + HCO3- hardness as CaCO3 Total hardness = 300 mg/L + 493.83 mg/L + 300 mg/L + 200 mg/L = 1293.83 mg/L
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Calculate the amount of lime required: Lime required = Total hardness * Volume of water / Purity of lime Lime required = 1293.83 mg/L * 106 L / 80% Lime required = 171.84 g
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Calculate the amount of soda required: Soda required = (Ca2+ hardness as CaCO3 + Mg2+ hardness as CaCO3) * Volume of water / Purity of soda Soda required = (300 mg/L + 493.83 mg/L) * 106 L / 90% Soda required = 94.14 g
So, 171.84 g of lime and 94.14 g of soda are required for softening of 106 litres of water.
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