A train crosses a bridge of length 600 m in the 40 s, another train of thesame length crosses a pole in 10s running at a speed of 20m/s. What is thespeed of the first train?

To solve this problem, we need to understand that when a train crosses a bridge, the distance covered is the length of the train plus the length of the bridge.

Step 1: First, let's find the length of the train. We know that the second train crosses a pole in 10 seconds at a speed of 20 m/s. When a train crosses a pole, the distance covered is equal to the length of the train. So, we can use the formula:

Speed = Distance/Time

Rearranging the formula to find the distance, we get:

Distance = Speed * Time

Substituting the given values:

Distance = 20 m/s * 10 s = 200 m

So, the length of the train is 200 m.

Step 2: Now, let's find the speed of the first train. We know that the first train crosses a bridge of length 600 m in 40 seconds. The total distance covered by the first train is the length of the train plus the length of the bridge, which is 200 m + 600 m = 800 m.

Using the formula Speed = Distance/Time, we get:

Speed = 800 m / 40 s = 20 m/s

So, the speed of the first train is 20 m/s.