Show that, when a charge of 180 000 C passes through the battery, the total amount of energy transferred to the battery is about 70 MJ.

To solve this problem, we need to use the formula for electrical energy, which is:

E = QV

where: E is the energy transferred, Q is the charge, V is the voltage.

We know that the charge Q is 180,000 C, but we don't have the voltage V. However, we can find it from the information given.

We know that the total energy transferred to the battery is about 70 MJ (Mega Joules). To convert this to Joules (since our formula requires the energy in Joules), we multiply by 1,000,000 (since 1 MJ = 1,000,000 J). So, E = 70,000,000 J.

Now we can substitute E and Q into the formula and solve for V:

70,000,000 J = 180,000 C * V

Divide both sides by 180,000 C to solve for V:

V = 70,000,000 J / 180,000 C = 388.89 V

So, the voltage is approximately 388.89 V.

Now, we can check our answer by substituting V and Q back into the formula:

E = QV = 180,000 C * 388.89 V = 70,000,002 J

This is approximately 70 MJ, so our answer is correct.