In a population of 1,000 individuals, a particular gene has two alleles: "A" and "a." The allele frequency for "A" is 0.6, and for "a," it is 0.4. According to the Hardy-Weinberg equilibrium, what would be the expected number of heterozygous individuals (Aa) in this population? 360 480 600 720

If the frequency of heterozygotes in a population of mice is 0.48 for a particular gene, what would be the frequency of heterozygotes in future generations if the population is in Hardy-Weinberg equilibrium?Multiple choice question.0.160.360.240.48

At a particular locus, the frequency of allele A is 0.8 and that of allele a is 0.2.What would be the frequency of heterozygotes in a random mating population atequilibrium?

Consider a very rare autosomal recessive disease, which affects only 1 in 40,000 individuals in a population. What is the expected frequency of heterozygotes in this population?Multiple choice question.about 1%about 2%about 5%about 0.005%

Which of the following describes a situation, in which the predominant genotype in a population in Hardy-Weinberg equilibrium is the heterozygote? Assume that the gene of interest has only two alleles: G and g.Multiple choice question.The allele frequencies of both G and g are intermediate in value.The allele frequency of g is low.The allele frequencies of G and g are very low.Incorrect. The allele frequencies of G and g are very high.

Consider a gene in a population of fruit bats. There are two alleles for this gene, A and a, that occur in a population with the frequencies 0.8 and 0.2, respectively. If the population is in Hardy-Weinberg equilibrium, what genotype frequencies will be observed?Multiple choice question.0.64 AA, 0.32 Aa, and 0.04 aa0.80 AA, 0.16 Aa, and 0.04 aa0.80 AA and 0.20 aa0.25 AA, 0.50 Aa, and 0.25 aa