Hemophilia is recessive sex-linked disease. When you cross a heterozygous female and a male without hemophilia, what is the phenotype fraction of the offspring that will have hemophilia? Question 9 options: 3/4 4/4 1/4 0/4 2/4
Question
Hemophilia is recessive sex-linked disease. When you cross a heterozygous female and a male without hemophilia, what is the phenotype fraction of the offspring that will have hemophilia?
Question 9 options:
3/4
4/4
1/4
0/4
2/4
Solution
Hemophilia is a sex-linked disease, which means it is carried on the X chromosome.
A heterozygous female (XHXh) has one X chromosome with the hemophilia gene (Xh) and one without (XH). A male without hemophilia has only one X chromosome, and it does not carry the hemophilia gene (XHY).
When you cross these two individuals, you get the following possible combinations:
- XHXH (healthy female)
- XHXh (carrier female)
- XHY (healthy male)
- XhY (male with hemophilia)
So, out of 4 possible outcomes, only 1 results in an offspring with hemophilia. Therefore, the phenotype fraction of the offspring that will have hemophilia is 1/4.
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