Consider a dihybrid cross between two trees given below that follow Mendelian inheritance pattern. How much percentage of grey short trees would you expect in F1 and F2 generation, respectively? 25% and 25% 25% and 50% 50% and 25% 50% and 50%

To answer this question, we first need to understand what a dihybrid cross is. A dihybrid cross is a breeding experiment between P generation (parental generation) organisms that differ in two traits.

However, the question does not provide enough information to answer it accurately. We need to know the genotypes of the parent trees and whether the traits are dominant or recessive.

In a typical Mendelian dihybrid cross where both traits are heterozygous (AaBb x AaBb), the F1 generation would all show the dominant traits (as they would all be heterozygous), and the F2 generation would show a phenotypic ratio of 9:3:3:1 (9 showing both dominant traits, 3 showing one dominant and one recessive trait, 3 showing the other dominant and the other recessive trait, and 1 showing both recessive traits).

So, if grey color and short height are both recessive traits, you would expect 1/16 of the F2 generation to be grey and short, which is approximately 6.25%. The F1 generation would all show the dominant traits, so 0% would be grey and short.

If grey color and short

To answer this question, we first need to understand what a dihybrid cross is. A dihybrid cross is a cross between two different lines (varieties, strains) that differ in two observed traits. In the Mendelian inheritance pattern, each parent contributes one of two possible alleles for a trait. If the two alleles are different, the dominant allele will be expressed, while the other allele, known as the recessive allele, is masked.

In the F1 generation, all offspring would be heterozygous for both traits, assuming that one parent is homozygous dominant for both traits and the other is homozygous recessive. This means that 100% of the F1 generation would display the dominant traits.

In the F2 generation, which is produced by crossing two individuals from the F1 generation, the traits can segregate in a 9:3:3:1 ratio according to Mendel's law of independent assortment. This means that 9/16 of the offspring will show both dominant traits, 3/16 will show one dominant and one recessive trait, 3/16 will show the other dominant and the other recessive trait, and 1/16 will show both recessive traits.

So, if grey and short are both recessive traits, we would expect 1/16 of the F2 generation to be grey and short, which is approximately 6.25%.

Therefore, the answer to your question would be 0% in the F1 generation and 6.25% in the F2 generation. However, this option is not provided in your list. Please check the question or the options again.