cos(a - B) + cos(a + B) = _____2sinasinB2cosacosB02(cosacosB + sinasinB)
Question
cos(a - B) + cos(a + B) = _____2sinasinB2cosacosB02(cosacosB + sinasinB)
Solution
The formula you're referring to is a trigonometric identity. The correct identity is:
cos(a - B) + cos(a + B) = 2cos(a)cos(B)
Here's the step by step derivation:
- We start with the sum-to-product identities for cosine, which are:
cos(A - B) = cos(A)cos(B) + sin(A)sin(B) cos(A + B) = cos(A)cos(B) - sin(A)sin(B)
- We add these two equations together:
cos(A - B) + cos(A + B) = [cos(A)cos(B) + sin(A)sin(B)] + [cos(A)cos(B) - sin(A)sin(B)]
- The sin(A)sin(B) terms cancel out, leaving us with:
cos(A - B) + cos(A + B) = 2cos(A)cos(B)
So, the correct answer to your question is 2cos(a)cos(B).
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