Consider the following code.x = [1]y = xz = x[:]x, y = z, zwhy there are 2 different objects will exist in the computer’s memory after the code has been executed?Assume that no optimizations have been performed and that garbage collection has been executed.
Question
Consider the following code.x = [1]y = xz = x[:]x, y = z, zwhy there are 2 different objects will exist in the computer’s memory after the code has been executed?Assume that no optimizations have been performed and that garbage collection has been executed.
Solution
The code you provided is creating and manipulating lists in Python. Here's a step-by-step explanation:
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x = [1]: This line creates a list with one element, 1, and assigns it to the variablex. This list is an object in memory. -
y = x: This line doesn't create a new list. Instead, it creates a new reference,y, to the same list thatxrefers to. So,xandyare two names for the same object in memory. -
z = x[:]: This line creates a new list that is a copy of the listxrefers to, and assigns it toz. The[:]is a slicing operation that returns a copy of the list. So now, there are two list objects in memory: the one thatxandyrefer to, and the one thatzrefers to. -
x, y = z, z: This line assigns the list thatzrefers to to bothxandy. Now,x,y, andzall refer to the same list object in memory. The original list thatxandyreferred to is no longer referenced by any variable, so it can be garbage collected.
So, after the code has been executed, there are two different list objects in memory: the one that x, y, and z refer to, and the original list that x and y referred to before the last line of code was executed. The latter list is no longer accessible through any variable, but it still exists in memory until it is garbage collected.
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Consider the following code. Assume that copy has been imported.w = [1, 2]z = copy.copy(w)z = copy.deepcopy(w)print(z + w)z = wwhy there are 3 different objects will exist in the computer’s memory after the code has been executed?Assume that no optimizations have been performed and that garbage collection has been executed.
How many different objects of type list exist in the computer’s memory after the followingcode has been executed? Assume that no garbage collection has been executed and that no optimizationshave been performed.import copya = [1, 2, 3, 9001]b = []for x in a:b = b + [x]c = aa = b[:]b = copy.deepcopy(b)
How does Python manage memory and garbage collection for objects that are no longer referenced in the code?
16. a = [1,2,3]b= aa == ba is bc = list(a)a == ca is cb == cWhich of the following statements is True?a is b: This statement checks if a and b reference the same object in memory, and it returns True.a == c: This statement checks if a and c contain the same elements, and it returns False because they are different objects.b == c: This statement checks if b and c contain the same elements, and it returns False because they reference different objects.a is c: This statement checks if a and c reference the same object in memory, and it returns True because they were created from the same list.
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