The number of zeros at the end of a factorial can be found by calculating the number of times 5 can divide the number. This is because 10 is the product of 2 and 5, and in a factorial, there are usually more 2s than 5s.

Here's how to calculate it:

1. Divide 101 by 5, you get 20 (ignore the remainder).
2. Divide 101 by 25 (5^2), you get 4.
3. Divide 101 by 125 (5^3), you get 0.

Add up these values (20 + 4 + 0), you get 24.

So, the number of zeros at the end of 101! is 24.

Therefore, the answer is D] 24.

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The number of zeros at the end of a factorial can be found by calculating the number of times 5 can divide the number. This is because 10 is the product of 2 and 5, and in a factorial, there are usually more 2s than 5s.

Here's how to calculate it:

1. Divide 101 by 5, you get 20 (ignore the remainder).
2. Divide 101 by 25 (5^2), you get 4.
3. Divide 101 by 125 (5^3), you get 0.

Add up these values (20 + 4 + 0), you get 24.

So, the number of zeros at the end of 101! is 24.

Therefore, the answer is D] 24.

Knowee AI · Accepted Answer

The number of zeros at the end of a factorial can be found by calculating the number of times 5 can divide the number. This is because 10 is the product of 2 and 5, and in a factorial, there are usually more 2s than 5s.

Here's how to calculate it:

1. Divide 101 by 5, you get 20 (ignore the remainder).
2. Divide 101 by 25 (5^2), you get 4.
3. Divide 101 by 125 (5^3), you get 0.

Add up these values (20 + 4 + 0), you get 24.

So, the number of zeros at the end of 101! is 24.

Therefore, the answer is D] 24.

Find the number of zeros in 101! A] 27 B] 21 C] 12 D] 24 Options : A B C D

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