A force of 20 N accelerates an object with a mass of 1201 g. What is the acceleration of the objects in m/s2, correct to one decimal place?

First, we need to convert the mass from grams to kilograms because the standard unit of mass in physics is kilograms.

1 kg = 1000 g

So, 1201 g = 1201/1000 = 1.201 kg

Next, we use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This can be written as:

F = ma

where: F is the force in Newtons, m is the mass in kilograms, and a is the acceleration in m/s².

We can rearrange the formula to solve for acceleration (a):

a = F/m

Substituting the given values:

a = 20 N / 1.201 kg = 16.65279 m/s²

Rounding to one decimal place, the acceleration of the object is 16.7 m/s².

First, we need to convert the mass from grams to kilograms because the standard unit of mass in physics is kilograms.

1 kg = 1000 g

So, 1201 g = 1201/1000 = 1.201 kg

Next, we use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This can be written as:

F = ma

where: F is the force in Newtons, m is the mass in kilograms, and a is the acceleration in m/s².

We can rearrange the formula to solve for acceleration (a):

a = F/m

Substituting the given values:

a = 20 N / 1.201 kg = 16.652 m/s²

Rounding to one decimal place, the acceleration of the object is 16.7 m/s².